{"id":1029,"date":"2019-02-10T09:10:51","date_gmt":"2019-02-10T09:10:51","guid":{"rendered":"https:\/\/blogs.ua.es\/dimates\/?p=1029"},"modified":"2019-02-17T08:08:07","modified_gmt":"2019-02-17T08:08:07","slug":"sucesion-e-igualdad-entre-productos","status":"publish","type":"post","link":"https:\/\/blogs.ua.es\/dimates\/2019\/02\/10\/sucesion-e-igualdad-entre-productos\/","title":{"rendered":"Sucesi\u00f3n e igualdad entre productos"},"content":{"rendered":"<pre>Problema 2 del viernes de la Fase Local de la LV OME 2019\r\nSe dirige a una edad de: 16-17 a\u00f1os<\/pre>\n<p>Demuestra que para todo n \u2265 2 podemos encontrar n n\u00fameros reales x<sub>1<\/sub>, x<sub>2<\/sub>, \u2026, x<sub>n<\/sub> \u2260 1 de manera que los productos x<sub>1<\/sub>\u00b7x<sub>2<\/sub>\u00b7&#8230;\u00b7x<sub>n<\/sub> y (1\/(1 \u2013 x<sub>1<\/sub>))\u00b7(1\/(1 \u2013 x<sub>2<\/sub>))\u00b7&#8230;\u00b7(1\/(1 \u2013 x<sub>n<\/sub>)) son iguales.<br \/>\n<img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/blogs.ua.es\/dimates\/files\/2019\/02\/80.Sucesionigualdadproducto.png\" alt=\"\" width=\"300\" height=\"300\" class=\"aligncenter size-full wp-image-1031\" srcset=\"https:\/\/blogs.ua.es\/dimates\/files\/2019\/02\/80.Sucesionigualdadproducto.png 300w, https:\/\/blogs.ua.es\/dimates\/files\/2019\/02\/80.Sucesionigualdadproducto-150x150.png 150w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><br \/>\nSoluci\u00f3n: <a href=\"https:\/\/blogs.ua.es\/dimates\/2019\/02\/16\/solucion-a-sucesion-e-igualdad-entre-productos\/\">Aqu\u00ed<\/a>.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Problema 2 del viernes de la Fase Local de la LV OME 2019 Se dirige a una edad de: 16-17 a\u00f1os Demuestra que para todo n \u2265 2 podemos encontrar n n\u00fameros reales x1, x2, \u2026, xn \u2260 1 de manera que los productos x1\u00b7x2\u00b7&#8230;\u00b7xn y (1\/(1 \u2013 x1))\u00b7(1\/(1 \u2013 x2))\u00b7&#8230;\u00b7(1\/(1 \u2013 xn)) son iguales. [&hellip;]<\/p>\n","protected":false},"author":4267,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[2242021,1738,2849],"tags":[],"class_list":["post-1029","post","type-post","status-publish","format-standard","hentry","category-olimpiada-matematica-espanola","category-olimpiadas","category-problemas"],"_links":{"self":[{"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/posts\/1029","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/users\/4267"}],"replies":[{"embeddable":true,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/comments?post=1029"}],"version-history":[{"count":3,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/posts\/1029\/revisions"}],"predecessor-version":[{"id":1037,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/posts\/1029\/revisions\/1037"}],"wp:attachment":[{"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/media?parent=1029"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/categories?post=1029"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/tags?post=1029"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}