{"id":1129,"date":"2019-04-14T08:25:28","date_gmt":"2019-04-14T08:25:28","guid":{"rendered":"https:\/\/blogs.ua.es\/dimates\/?p=1129"},"modified":"2019-04-27T20:19:27","modified_gmt":"2019-04-27T20:19:27","slug":"triangulos-girados","status":"publish","type":"post","link":"https:\/\/blogs.ua.es\/dimates\/2019\/04\/14\/triangulos-girados\/","title":{"rendered":"Tri\u00e1ngulos girados"},"content":{"rendered":"<pre>Problema 1 de la Fase Comarcal de la de la XXX OMCV 2019\r\nSe dirige a una edad de: 12-13 a\u00f1os<\/pre>\n<p>Tenemos dos tri\u00e1ngulos equil\u00e1teros iguales, que forman uno con otro un \u00e1ngulo de 80\u00ba en el v\u00e9rtice que se tocan.<\/p>\n<p>Unimos un v\u00e9rtice de un tri\u00e1ngulo con el que est\u00e1 en la otra posici\u00f3n del otro (no con el sim\u00e9trico).<\/p>\n<p>\u00bfQu\u00e9 \u00e1ngulo forma este segmento con el lateral del tri\u00e1ngulo que no toca el v\u00e9rtice que los une?<br \/>\n<img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/blogs.ua.es\/dimates\/files\/2019\/04\/89.Encuentraelangulo.png\" alt=\"\" width=\"300\" height=\"300\" class=\"aligncenter size-full wp-image-1130\" srcset=\"https:\/\/blogs.ua.es\/dimates\/files\/2019\/04\/89.Encuentraelangulo.png 300w, https:\/\/blogs.ua.es\/dimates\/files\/2019\/04\/89.Encuentraelangulo-150x150.png 150w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><br \/>\nSoluci\u00f3n: <a href=\"https:\/\/blogs.ua.es\/dimates\/2019\/04\/20\/solucion-a-triangulos-girados\/\">Aqu\u00ed<\/a>.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Problema 1 de la Fase Comarcal de la de la XXX OMCV 2019 Se dirige a una edad de: 12-13 a\u00f1os Tenemos dos tri\u00e1ngulos equil\u00e1teros iguales, que forman uno con otro un \u00e1ngulo de 80\u00ba en el v\u00e9rtice que se tocan. Unimos un v\u00e9rtice de un tri\u00e1ngulo con el que est\u00e1 en la otra posici\u00f3n [&hellip;]<\/p>\n","protected":false},"author":4267,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[2242020,1738,2849],"tags":[],"class_list":["post-1129","post","type-post","status-publish","format-standard","hentry","category-olimpiada-de-la-comunidad-valenciana","category-olimpiadas","category-problemas"],"_links":{"self":[{"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/posts\/1129","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/users\/4267"}],"replies":[{"embeddable":true,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/comments?post=1129"}],"version-history":[{"count":2,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/posts\/1129\/revisions"}],"predecessor-version":[{"id":1144,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/posts\/1129\/revisions\/1144"}],"wp:attachment":[{"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/media?parent=1129"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/categories?post=1129"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/tags?post=1129"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}