{"id":137,"date":"2017-09-02T16:41:51","date_gmt":"2017-09-02T16:41:51","guid":{"rendered":"https:\/\/blogs.ua.es\/dimates\/?p=137"},"modified":"2017-09-08T19:04:22","modified_gmt":"2017-09-08T19:04:22","slug":"sucesion-estancada","status":"publish","type":"post","link":"https:\/\/blogs.ua.es\/dimates\/2017\/09\/02\/sucesion-estancada\/","title":{"rendered":"Sucesi\u00f3n estancada"},"content":{"rendered":"<pre>Olimpiada Matem\u00e1tica Internacional 2017, problema 1.\r\nSe dirige a una edad de: 16\/17<\/pre>\n<p>Para cada entero a<sub>0<\/sub> &gt; 1, se define la sucesi\u00f3n a<sub>0<\/sub>, a<sub>1<\/sub>, a<sub>2<\/sub>, &#8230; tal que para cada n \u2265 0: a<sub>n + 1<\/sub> = \u221a(a<sub>n<\/sub>), siempre que \u221a(a<sub>n<\/sub>) sea entero, mientras que a<sub>n + 1<\/sub> = a<sub>n<\/sub> + 3 en cualquier otro caso.<\/p>\n<p>Determinar todos los valores de a<sub>0<\/sub> para los que existe un n\u00famero A tal que a<sub>n<\/sub> = A para infinitos valores de n.<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-medium wp-image-139\" src=\"https:\/\/blogs.ua.es\/dimates\/files\/2017\/09\/9.sucesionestancada-300x195.png\" alt=\"\" width=\"300\" height=\"195\" \/><\/p>\n<p>Soluci\u00f3n: <a href=\"https:\/\/blogs.ua.es\/dimates\/2017\/09\/08\/sucesion-estancada-s\/\">Aqu\u00ed<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Olimpiada Matem\u00e1tica Internacional 2017, problema 1. Se dirige a una edad de: 16\/17 Para cada entero a0 &gt; 1, se define la sucesi\u00f3n a0, a1, a2, &#8230; tal que para cada n \u2265 0: an + 1 = \u221a(an), siempre que \u221a(an) sea entero, mientras que an + 1 = an + 3 en cualquier [&hellip;]<\/p>\n","protected":false},"author":4267,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1738,2849],"tags":[],"class_list":["post-137","post","type-post","status-publish","format-standard","hentry","category-olimpiadas","category-problemas"],"_links":{"self":[{"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/posts\/137","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/users\/4267"}],"replies":[{"embeddable":true,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/comments?post=137"}],"version-history":[{"count":6,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/posts\/137\/revisions"}],"predecessor-version":[{"id":149,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/posts\/137\/revisions\/149"}],"wp:attachment":[{"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/media?parent=137"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/categories?post=137"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/tags?post=137"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}