{"id":1655,"date":"2020-05-24T07:10:06","date_gmt":"2020-05-24T07:10:06","guid":{"rendered":"https:\/\/blogs.ua.es\/dimates\/?p=1655"},"modified":"2020-05-30T18:22:00","modified_gmt":"2020-05-30T18:22:00","slug":"dos-ortoedros-unidos","status":"publish","type":"post","link":"https:\/\/blogs.ua.es\/dimates\/2020\/05\/24\/dos-ortoedros-unidos\/","title":{"rendered":"Dos ortoedros unidos"},"content":{"rendered":"<pre>Problema 7 del concurso marat\u00f3 de problemes 2020\r\nSe dirige a una edad de: 14-15 a\u00f1os<\/pre>\n<p>Un ortoedro es un poliedro con seis caras rectangulares perpendiculares cada una de ellas a sus vecinas.<\/p>\n<p>Supongamos que tenemos dos octoedros que tienen la particularidad de que pueden unirse por una de sus caras para formar un ortoedro mayor.<\/p>\n<p>Demuestra que, si la superficie total del ortoedro mayor es exactamente 3\/4 de la suma de las superficies de los dos originales, entonces las dimensiones del ortoedro mayor x, y, z cumplen la relaci\u00f3n 1\/x + 1\/y = 2\/z.<br \/>\n<img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/blogs.ua.es\/dimates\/files\/2020\/05\/146.Cuboide2.gif\" alt=\"\" width=\"420\" height=\"420\" class=\"aligncenter size-full wp-image-1656\" \/><br \/>\nSoluci\u00f3n: <a href=\"https:\/\/blogs.ua.es\/dimates\/2020\/05\/30\/solucion-a-dos-ortoedros-unidos\/\">Aqu\u00ed<\/a>.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Problema 7 del concurso marat\u00f3 de problemes 2020 Se dirige a una edad de: 14-15 a\u00f1os Un ortoedro es un poliedro con seis caras rectangulares perpendiculares cada una de ellas a sus vecinas. Supongamos que tenemos dos octoedros que tienen la particularidad de que pueden unirse por una de sus caras para formar un ortoedro [&hellip;]<\/p>\n","protected":false},"author":4267,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[2242026,1738,2849],"tags":[],"class_list":["post-1655","post","type-post","status-publish","format-standard","hentry","category-marato-de-problemes","category-olimpiadas","category-problemas"],"_links":{"self":[{"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/posts\/1655","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/users\/4267"}],"replies":[{"embeddable":true,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/comments?post=1655"}],"version-history":[{"count":2,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/posts\/1655\/revisions"}],"predecessor-version":[{"id":1660,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/posts\/1655\/revisions\/1660"}],"wp:attachment":[{"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/media?parent=1655"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/categories?post=1655"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/tags?post=1655"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}