{"id":1853,"date":"2020-12-06T20:59:20","date_gmt":"2020-12-06T20:59:20","guid":{"rendered":"https:\/\/blogs.ua.es\/dimates\/?p=1853"},"modified":"2020-12-19T09:25:24","modified_gmt":"2020-12-19T09:25:24","slug":"un-hexagono-en-un-triangulo","status":"publish","type":"post","link":"https:\/\/blogs.ua.es\/dimates\/2020\/12\/06\/un-hexagono-en-un-triangulo\/","title":{"rendered":"Un hex\u00e1gono en un tri\u00e1ngulo"},"content":{"rendered":"<pre>Problema 14 del concurso marat\u00f3 de problemes 2019\r\nSe dirige a una edad de: 14-15 a\u00f1os<\/pre>\n<p>En un tri\u00e1ngulo acut\u00e1ngulo trazamos, desde el punto medio de cada lado, las dos perpendiculares a los otros dos lados.<br \/>\nJustifica que estas 6 rectas forman un hex\u00e1gono.<\/p>\n<p>\u00bfQu\u00e9 valor tiene la raz\u00f3n entre las \u00e1reas del tri\u00e1ngulo y del hex\u00e1gono?<\/p>\n<p>Demuestra que la raz\u00f3n que has calculado es constante, es decir, no depende de cu\u00e1l sea el tri\u00e1ngulo inicial.<br \/>\n<img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/blogs.ua.es\/dimates\/files\/2020\/12\/172.Hexagonoentriangulo.png\" alt=\"\" width=\"300\" height=\"300\" class=\"aligncenter size-full wp-image-1854\" srcset=\"https:\/\/blogs.ua.es\/dimates\/files\/2020\/12\/172.Hexagonoentriangulo.png 300w, https:\/\/blogs.ua.es\/dimates\/files\/2020\/12\/172.Hexagonoentriangulo-150x150.png 150w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><br \/>\nSoluci\u00f3n: <a href=\"https:\/\/blogs.ua.es\/dimates\/2020\/12\/12\/solucion-a-un-hexagono-en-un-triangulo\/\">Aqu\u00ed<\/a>.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Problema 14 del concurso marat\u00f3 de problemes 2019 Se dirige a una edad de: 14-15 a\u00f1os En un tri\u00e1ngulo acut\u00e1ngulo trazamos, desde el punto medio de cada lado, las dos perpendiculares a los otros dos lados. Justifica que estas 6 rectas forman un hex\u00e1gono. \u00bfQu\u00e9 valor tiene la raz\u00f3n entre las \u00e1reas del tri\u00e1ngulo y [&hellip;]<\/p>\n","protected":false},"author":4267,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[2242026,1738,2849],"tags":[],"class_list":["post-1853","post","type-post","status-publish","format-standard","hentry","category-marato-de-problemes","category-olimpiadas","category-problemas"],"_links":{"self":[{"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/posts\/1853","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/users\/4267"}],"replies":[{"embeddable":true,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/comments?post=1853"}],"version-history":[{"count":2,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/posts\/1853\/revisions"}],"predecessor-version":[{"id":1870,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/posts\/1853\/revisions\/1870"}],"wp:attachment":[{"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/media?parent=1853"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/categories?post=1853"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/tags?post=1853"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}