{"id":281,"date":"2017-12-03T09:56:05","date_gmt":"2017-12-03T09:56:05","guid":{"rendered":"https:\/\/blogs.ua.es\/dimates\/?p=281"},"modified":"2018-09-15T07:01:40","modified_gmt":"2018-09-15T07:01:40","slug":"un-cuadrilatero-en-un-paralelogramo","status":"publish","type":"post","link":"https:\/\/blogs.ua.es\/dimates\/2017\/12\/03\/un-cuadrilatero-en-un-paralelogramo\/","title":{"rendered":"Un cuadril\u00e1tero en un paralelogramo"},"content":{"rendered":"<pre>Canguro matem\u00e1tico (nivel 3) 2017\r\nSe dirige a una edad de: 14 a\u00f1os<\/pre>\n<p>ABCD es un paralelogramo.<img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-full wp-image-282\" src=\"https:\/\/blogs.ua.es\/dimates\/files\/2017\/12\/21.cuadrilateroenparalelogramo.png\" alt=\"\" width=\"300\" height=\"300\" srcset=\"https:\/\/blogs.ua.es\/dimates\/files\/2017\/12\/21.cuadrilateroenparalelogramo.png 300w, https:\/\/blogs.ua.es\/dimates\/files\/2017\/12\/21.cuadrilateroenparalelogramo-150x150.png 150w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><\/p>\n<p>El punto O es la intersecci\u00f3n de las diagonales del paralelogramo. El punto M est\u00e1 en el lado DC. El punto de intersecci\u00f3n de BM y AC es F. La suma de las \u00e1reas de los tri\u00e1ngulos AED y BFC es 1\/3 del \u00e1rea S del paralelogramo.<\/p>\n<p>\u00bfCu\u00e1nto vale el \u00e1rea del cuadril\u00e1tero EOFM, en funci\u00f3n de S?<\/p>\n<p>Puesto que el concurso es de respuesta cerrada, se nos ofrec\u00edan cuatro alternativas, S\/6, S\/8, S\/10, S\/12 y S\/14.<\/p>\n<p>Soluci\u00f3n: <a href=\"https:\/\/blogs.ua.es\/dimates\/2017\/12\/09\/a-un-cuadrilatero-en-un-paralelogramo-s\/\">aqu\u00ed<\/a>.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Canguro matem\u00e1tico (nivel 3) 2017 Se dirige a una edad de: 14 a\u00f1os ABCD es un paralelogramo. El punto O es la intersecci\u00f3n de las diagonales del paralelogramo. El punto M est\u00e1 en el lado DC. El punto de intersecci\u00f3n de BM y AC es F. La suma de las \u00e1reas de los tri\u00e1ngulos AED [&hellip;]<\/p>\n","protected":false},"author":4267,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[2849],"tags":[],"class_list":["post-281","post","type-post","status-publish","format-standard","hentry","category-problemas"],"_links":{"self":[{"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/posts\/281","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/users\/4267"}],"replies":[{"embeddable":true,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/comments?post=281"}],"version-history":[{"count":2,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/posts\/281\/revisions"}],"predecessor-version":[{"id":296,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/posts\/281\/revisions\/296"}],"wp:attachment":[{"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/media?parent=281"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/categories?post=281"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/tags?post=281"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}