{"id":2975,"date":"2023-08-12T09:54:52","date_gmt":"2023-08-12T09:54:52","guid":{"rendered":"https:\/\/blogs.ua.es\/dimates\/?p=2975"},"modified":"2023-08-29T08:06:06","modified_gmt":"2023-08-29T08:06:06","slug":"el-area-del-triangulo","status":"publish","type":"post","link":"https:\/\/blogs.ua.es\/dimates\/2023\/08\/12\/el-area-del-triangulo\/","title":{"rendered":"El \u00e1rea del tri\u00e1ngulo"},"content":{"rendered":"<pre>Problema 3 del primer nivel de la Olimpiada de Mayo 2023\r\nSe dirige a una edad de: 11-12 a\u00f1os<\/pre>\n<p>Sobre una recta l hay cuatro puntos, A, B, C y D en ese orden, tales que AB = BC = CD.<\/p>\n<p>Se elige un punto E fuera de la recta l de modo que al trazar los segmentos EB y EC se forme un tri\u00e1ngulo equil\u00e1tero EBC.<\/p>\n<p>A continuaci\u00f3n se trazan los segmentos EA y ED y se elige un punto F de modo que al trazar los segmentos FA y FE se forme un tri\u00e1ngulo equil\u00e1tero FAE exterior al tri\u00e1ngulo EAD.<\/p>\n<p>Por \u00faltimo se trazan las rectas EB y FA, que se cortan en el punto G.<\/p>\n<p>Si el \u00e1rea del tri\u00e1ngulo EBD es 10, calcula el \u00e1rea del tri\u00e1ngulo EFG.<br \/>\n<img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/blogs.ua.es\/dimates\/files\/2023\/08\/311.Area_.png\" alt=\"\" width=\"300\" height=\"300\" class=\"alignnone size-full wp-image-2976\" srcset=\"https:\/\/blogs.ua.es\/dimates\/files\/2023\/08\/311.Area_.png 300w, https:\/\/blogs.ua.es\/dimates\/files\/2023\/08\/311.Area_-150x150.png 150w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><br \/>\nSoluci\u00f3n: <a href=\"https:\/\/blogs.ua.es\/dimates\/2023\/08\/19\/solucion-a-el-area-de-un-triangulo-2\/\">Aqu\u00ed<\/a>.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Problema 3 del primer nivel de la Olimpiada de Mayo 2023 Se dirige a una edad de: 11-12 a\u00f1os Sobre una recta l hay cuatro puntos, A, B, C y D en ese orden, tales que AB = BC = CD. Se elige un punto E fuera de la recta l de modo que al [&hellip;]<\/p>\n","protected":false},"author":4267,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[2242027,1738,2849],"tags":[],"class_list":["post-2975","post","type-post","status-publish","format-standard","hentry","category-mayo","category-olimpiadas","category-problemas"],"_links":{"self":[{"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/posts\/2975","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/users\/4267"}],"replies":[{"embeddable":true,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/comments?post=2975"}],"version-history":[{"count":2,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/posts\/2975\/revisions"}],"predecessor-version":[{"id":3003,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/posts\/2975\/revisions\/3003"}],"wp:attachment":[{"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/media?parent=2975"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/categories?post=2975"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/tags?post=2975"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}