{"id":3071,"date":"2023-10-28T06:33:45","date_gmt":"2023-10-28T06:33:45","guid":{"rendered":"https:\/\/blogs.ua.es\/dimates\/?p=3071"},"modified":"2023-11-05T12:49:53","modified_gmt":"2023-11-05T12:49:53","slug":"triangulo-rectangulo","status":"publish","type":"post","link":"https:\/\/blogs.ua.es\/dimates\/2023\/10\/28\/triangulo-rectangulo\/","title":{"rendered":"Tri\u00e1ngulo rect\u00e1ngulo"},"content":{"rendered":"<pre>Problema 7 del concurso Olitele 2022\r\nSe dirige a una edad de: 16-17 a\u00f1os<\/pre>\n<p>En el tri\u00e1ngulo rect\u00e1ngulo AED de la figura, rect\u00e1ngulo en E, AB es la altura sobre la hipotenusa y EC es la bisectriz del \u00e1ngulo recto.<\/p>\n<p>Si se cumple que la raz\u00f3n de distancias entre AC y CD es 1:3, razona cu\u00e1l es la proporci\u00f3n entre las distancias de los tres segmentos AB, BC y CD en que ha quedado dividida la hipotenusa.<\/p>\n<p>Nota: seguramente no es la \u00fanica manera de enfocar el problema, pero puede ser interesante que se comience por calcular la relaci\u00f3n de distancias AB:BD.<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-3072\" src=\"https:\/\/blogs.ua.es\/dimates\/files\/2023\/10\/321.triangulo.png\" alt=\"\" width=\"300\" height=\"300\" srcset=\"https:\/\/blogs.ua.es\/dimates\/files\/2023\/10\/321.triangulo.png 300w, https:\/\/blogs.ua.es\/dimates\/files\/2023\/10\/321.triangulo-150x150.png 150w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><\/p>\n<p>Soluci\u00f3n: <a href=\"https:\/\/blogs.ua.es\/dimates\/2023\/11\/05\/solucion-a-triangulo-rectangulo\/\">Aqu\u00ed<\/a>.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Problema 7 del concurso Olitele 2022 Se dirige a una edad de: 16-17 a\u00f1os En el tri\u00e1ngulo rect\u00e1ngulo AED de la figura, rect\u00e1ngulo en E, AB es la altura sobre la hipotenusa y EC es la bisectriz del \u00e1ngulo recto. Si se cumple que la raz\u00f3n de distancias entre AC y CD es 1:3, razona [&hellip;]<\/p>\n","protected":false},"author":4267,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1738,2242014,2849],"tags":[],"class_list":["post-3071","post","type-post","status-publish","format-standard","hentry","category-olimpiadas","category-olitele","category-problemas"],"_links":{"self":[{"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/posts\/3071","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/users\/4267"}],"replies":[{"embeddable":true,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/comments?post=3071"}],"version-history":[{"count":2,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/posts\/3071\/revisions"}],"predecessor-version":[{"id":3078,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/posts\/3071\/revisions\/3078"}],"wp:attachment":[{"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/media?parent=3071"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/categories?post=3071"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/tags?post=3071"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}