{"id":314,"date":"2017-12-25T22:09:02","date_gmt":"2017-12-25T22:09:02","guid":{"rendered":"https:\/\/blogs.ua.es\/dimates\/?p=314"},"modified":"2018-01-15T19:48:11","modified_gmt":"2018-01-15T19:48:11","slug":"un-par-de-angulos","status":"publish","type":"post","link":"https:\/\/blogs.ua.es\/dimates\/2017\/12\/25\/un-par-de-angulos\/","title":{"rendered":"Un par de \u00e1ngulos"},"content":{"rendered":"<pre>Canguro matem\u00e1tico (nivel 5) 2017\r\nSe dirige a una edad de: 16 a\u00f1os<\/pre>\n<p>ABC es un tri\u00e1ngulo. El punto D se elige de forma que DC = AB.<\/p>\n<p>El punto M es el punto medio entre A y D, y el punto N es el punto medio entre B y C.<\/p>\n<p>Si entendemos que el \u00e1ngulo NMC es x, entonces, el \u00e1ngulo BAC \u00bfqu\u00e9 vale, en funci\u00f3n de x?<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-medium wp-image-315\" src=\"https:\/\/blogs.ua.es\/dimates\/files\/2017\/12\/24.Unpardeangulos-300x263.png\" alt=\"\" width=\"300\" height=\"263\" \/><\/p>\n<p>Puesto que el concurso es de respuesta cerrada, se nos ofrec\u00edan cinco alternativas:\u00a0 2x, 90 \u2013 x, 45 + x, 90 \u2013 x\/2, o 60\u00ba.<\/p>\n<p>Soluci\u00f3n: <a href=\"https:\/\/blogs.ua.es\/dimates\/2017\/12\/30\/un-par-de-angulos-s\/\">Aqu\u00ed<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Canguro matem\u00e1tico (nivel 5) 2017 Se dirige a una edad de: 16 a\u00f1os ABC es un tri\u00e1ngulo. El punto D se elige de forma que DC = AB. El punto M es el punto medio entre A y D, y el punto N es el punto medio entre B y C. Si entendemos que el [&hellip;]<\/p>\n","protected":false},"author":4267,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[2849],"tags":[],"class_list":["post-314","post","type-post","status-publish","format-standard","hentry","category-problemas"],"_links":{"self":[{"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/posts\/314","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/users\/4267"}],"replies":[{"embeddable":true,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/comments?post=314"}],"version-history":[{"count":3,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/posts\/314\/revisions"}],"predecessor-version":[{"id":343,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/posts\/314\/revisions\/343"}],"wp:attachment":[{"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/media?parent=314"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/categories?post=314"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blogs.ua.es\/dimates\/wp-json\/wp\/v2\/tags?post=314"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}